Question

The students of a class arranged a gift for the class teacher. Each student
contributed as many rupees as the number of students in the class. If the total
contribution is Rs 1521, find the strength of the class.​

Answer 1

Answer:

ANSWER IS 39 . IT IS OBTAINED BY SQUARE ROOT OF 1521 .PLEASE MARK IT AS BRAINLIEST.

Answer 2

The strength of the class = 39

Given :

• The students of a class arranged a gift for the class teacher.

• Each student contributed as many rupees as the number of students in the class.

• The total contribution is Rs. 1521

To find :

The strength of the class

Solution :

Step 1 of 2 :

Form the equation to find the strength of the class

Let strength of the class = n

Now it is given that each student contributed as many rupees as the number of students in the class.

∴ Contribution by each student = Rs. n

∴ Total contribution

= Rs. (n × n)

= Rs. n²

Again it is given that total contribution is Rs. 1521

By the given condition

$\displaystyle \sf{ {n}^{2} = 1521 }$

Step 2 of 2 :

Calculate strength of the class

$\displaystyle \sf{ {n}^{2} = 1 521}$

$\displaystyle \sf{ \implies n = \sqrt{1521} }$

Now we find the square root of 1521 as below

$\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\:39\:\:}}}\\ {\underline{\sf{3}}}& {\sf{1521}} \\{\sf{}}& \underline{\sf{ \: \: \: \: \: \: \: \: 9 \: \: \: \: \: \: \: \: \: \: \: \: }} \\ {\underline{\sf{69}}}& {\sf{\: \: \: \: \: \: \: \: \: 621 \: \: \: \: \: \: \: \: \: }} \\{\sf{}}&\underline{\sf{ \: \: \: \: \: \: 621 \: \: \: \: \: \: }} \\ {\underline{\sf{}}}&{\sf{\:\:0 \:\:}} {\sf{}}&{\sf{\:\:\:\:}}\end{array}\end{gathered}$

$\displaystyle \sf{ \therefore \: \: \sqrt{1521} = 39 }$

$\displaystyle \sf{ \therefore \: \: n = \sqrt{1521} = 39 }$

Hence strength of the class = 39

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ The value of 405suare-404 sqaure

https://brainly.in/question/49743792

2. Find the value of 399^2- 398^2

https://brainly.in/question/10363843

#SPJ3