Question

The students while solving a quadratic equation in x, one copied the constant term incorrectly and got the roots 3 and 2. The other copied the constant term and coefficient of x^2 as -6 and 1 Respectively the correct roots are

with explanation please​

Answer 1

Step-by-step explanation:

Letthecorrectequationbex2+ax−6,

Lettheincorrectequationbex2+ax+b,

b=productofroots=2×3=6,

a=−sumofroots=−(2+3)=−5,

Thereforethecorrectequationisgivenby

x2−5x−6=0x2−6x+x−6=0(x−6)(x+1)=0,x=−1,6