The sub shell electronic configuration of an element A is given below in two ways(symbol is not real)
i) 1s2 2s2 2p6 3s2 3p6 3d1
i) 1s2 2s2 2p6 3s2 3p6 4s1
a) which configuration is correct .
b) the above element belongs to which block in the periodic table.
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Answer:
1s2, 2s2, 2p6, 3s2, 3p6, 4s1 is correct configuration.
b) the above element belongs to fourth block of periodic table.
Explanation:
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