Question

The succesive I. p values of anelement more
120,600,1000 and 8000 Kolmol respectively Then
formula of its sulphide will be​

Answer 1

Answer: the answer is  X2S3

Explanation:

let the element(unknown) be X and when we observe the ip values trend there is a sudden increase for the 4th electron i.e, it's valence shell consists only 3 electrons .

and hence its valency is 3.

so the formula of its sulphide is X2S3.

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