Question

The successive ionization energies for an unknown element are :
IE, = 889 KJ/mol : IE, = 1757 KJ/mol.
IE, = 14,847 KJ/mol. ; IE, = 17,948 KJ/mol.
To which group in the periodic table does the unknown element most likely
belong?​

Answer 1

Answer:

most likely the element is in group 2

Explanation:

we see that the 3rd IE >> 2nd IE

So, it means that when it loses 2 electrons it is relatively stable......that means that it lies in group 2.

Answer 2

Answer:

ie =889 kj/ mol is unkown element and please Mark me in brain list and please subscribe my YouTube channel