Question

The successive ionization energy values for an element 'x' are given below
i) 1st IP = 410 KJ/mole
ii) 2nd IP = 820 KJ/mole
ii) 3rd IP =1100 KJ/mole
iv) 4th [P = 1500 KJ/
mole
v) 5th P = 3200 KJ/mole
What are the number of valance electron for an atom x?​

Answer 1

Answer:

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Explanation:

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