the sulphate of a metal M contains 9.87% of M.This sulphate is isomorphous with ZNSO4.7H2O.The atomic weight of M is a.) 40.3 b.) 36.3 c.) 24.3 d) 11.3
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molecular weight of the metal = M
Now as it is isomorphous with ZnSO4.7H2O it would be of the formula MSO4.7H2O
Percentage of M in the compound= M x 100/ M + weight of SO4 + 7 x weight of H2O
=M x 100/ M + weight of SO4 + 7 x weight of H2O
=M x 100/ M + 96 + 126
=M x 100/ M + 96 + 126
=9.87
Now as it is isomorphous with ZnSO4.7H2O it would be of the formula MSO4.7H2O
Percentage of M in the compound= M x 100/ M + weight of SO4 + 7 x weight of H2O
=M x 100/ M + weight of SO4 + 7 x weight of H2O
=M x 100/ M + 96 + 126
=M x 100/ M + 96 + 126
=9.87
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Answer:
(c) 24.3
here's the answer and hope this helps you.
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