Chemistry, asked by karansingh6358, 1 year ago

The sulphate of an element contains 42.2% element, the equivalent weight should be:-

Answers

Answered by danielochich
16
Since it is a Sulphate, the formulae for the Sulphate would be :

Let X be the element hen the formula would be :

XSO₄

Since the element is 42.2%, the SO₄ would be :

100% - 42.2% = 57.8%

Molar mass of SO₄:

64 + 32 = 96g / mole

This represents 57.8%

Mass of element is thus :

(0.422 / 0.578) × 96 = 70.09

Answered by Anonymous
7

Answer:

Explanation:

Since it is a Sulphate, the formulae for the Sulphate would be :

Let X be the element hen the formula would be :

XSO₄

Since the element is 42.2%, the SO₄ would be :

100% - 42.2% = 57.8%

Molar mass of SO₄:

64 + 32 = 96g / mole

This represents 57.8%

Mass of element is thus :

(0.422 / 0.578) × 96 = 70.09

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