The sulphate of an element contains 42.2% element, the equivalent weight should be:-
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Since it is a Sulphate, the formulae for the Sulphate would be :
Let X be the element hen the formula would be :
XSO₄
Since the element is 42.2%, the SO₄ would be :
100% - 42.2% = 57.8%
Molar mass of SO₄:
64 + 32 = 96g / mole
This represents 57.8%
Mass of element is thus :
(0.422 / 0.578) × 96 = 70.09
Let X be the element hen the formula would be :
XSO₄
Since the element is 42.2%, the SO₄ would be :
100% - 42.2% = 57.8%
Molar mass of SO₄:
64 + 32 = 96g / mole
This represents 57.8%
Mass of element is thus :
(0.422 / 0.578) × 96 = 70.09
Answered by
7
Answer:
Explanation:
Since it is a Sulphate, the formulae for the Sulphate would be :
Let X be the element hen the formula would be :
XSO₄
Since the element is 42.2%, the SO₄ would be :
100% - 42.2% = 57.8%
Molar mass of SO₄:
64 + 32 = 96g / mole
This represents 57.8%
Mass of element is thus :
(0.422 / 0.578) × 96 = 70.09
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