Chemistry, asked by tarushisaxena96641, 1 year ago

The sulphur present in an organic compound is oxidised by fuming hno3 into

Answers

Answered by rkd55
1
Estimation of sulphur: A known mass of an organic compound is heated in a Carius tube with sodium peroxide orfuming nitric acid. Sulphur present in the compound is oxidised to sulphuric acid. It is precipitated as barium sulphate by adding an excess of barium chloride solution in water.
Answered by arshaarunsl
0

Answer:

In a Carius tube, a known mass of an organic chemical is heated with sodium peroxide or fuming nitric acid. The compound's Sulphur is oxidized to Sulphuric acid.

Explanation:

Estimation of Sulphur:

  • A known mass of Sulphur-containing organic compound is heated in a sealed Carius tube in the presence of excess fuming nitric acid in the Carius method.
  • Sulphur is present in this organic molecule, which is converted to Sulphuric acid.

Sulphur test:

  • Before being combined with lead acetate, the sodium fusion extract is acidified with acetic acid.
  • The presence of Sulphur is indicated by a dark precipitate of lead(II) Sulphide.

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