Question

The sum 2 numbers is 64. The second number is 16 less than the first. Find the numbers.
(Please answer with steps)

(WARNING:UNNECESSARY ANSWERS WILL BE REPORTED)​

Answer 1

Answer:

Given :-

• The sum of two numbers is 64.
• The second number is 16 less than the first.

To Find :-

• What are the numbers.

Solution :-

Let,

$\mapsto \bf First\: Number =\: x$

$\mapsto \bf Second\: Number =\: x - 16$

According to the question,

$\bigstar$ The sum of two numbers is 64.

$\small \implies \bf \bigg[First\: Number\bigg] + \bigg[Second\: Number\bigg] =\: 64$

$\implies \sf x + (x - 16) =\: 64$

$\implies \sf x + x - 16 =\: 64$

$\implies \sf 2x =\: 64 + 16$

$\implies \sf 2x =\: 80$

$\implies \sf x =\: \dfrac{\cancel{80}}{\cancel{2}}$

$\implies \sf\bold{\purple{x =\: 40}}$

Hence, the required numbers are :

$\clubsuit\: \: \sf\bold{\green{First\: Number\: :-}}$

$\leadsto \sf First\: Number =\: x$

$\leadsto \sf\boxed{\bold{\red{First\: Number =\: 40}}}$

$\clubsuit \: \: \sf\bold{\green{Second\: Number\: :-}}$

$\leadsto \sf Second\: Number =\: x - 16$

$\leadsto \sf Second\: Number =\: 40 - 16$

$\leadsto \sf\boxed{\bold{\red{Second\: Number =\: 24}}}$

$\therefore$ The numbers are 24 and 40.

Answer 2

Answer:

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