the sum 3 concustive multiple of 9 is 108 find the number
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Let that three consecutive multiples of 9 be x+9, x+18, x+27
Therefore from given condition,
x+9+x+18+x+27=108
3x+54=108
3x=108-54
3x=54
x=54/3
x=18
therefore first number,
x+9=18+9=27
second number,
x+18=18+18=36
third number,
x+27=18+27=45
therefore, the numbers are 27,36,45
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