Question

The sum all natural numbers from 75 to 97

Answer 1

answer it by A.P.
a(n) = a(n-1)d
d = common difference
n = no. of terms
a = total sum

Answer 2

Answer:

$75+76+77+78+79+80+81+82+83+84+85+86+87+88+89+90+91+92+93+94+95+96+97=2018$

Step-by-step explanation:

$75+76+77+78+79+80+81+82+83+84+85+86+87+88+89+90+91+92+93+94+95+96+97=$

Firstly, add up the numbers 75,76, 77, 78, 79 and 80.

$75+76+77+78+79+80=151+77+78+79+80=228+78+79+80=306+79+80=385+80=465$

Then, add up the numbers 81-90 in the easiest way possible. See what I mean:

$81+82+83+84+85+86+87+88+89+90=81+89+82+88+83+87+84+86+85+90=180+180+180+180+85+90=180*4+175=895$

After that, add up the numbers 91-97.

$91+92+93+94+95+96+97=183+93+94+95+96+97=276+94+95+96+97=370+95+96+97=465+96+97=561+97=658$

Lastly, add of the numbers up.

$465+895+658=1360+658=2018$

Brainliest answer pleaseee ^w^