Question

the sum and difference of two angles of a triangle are 120 degree and 22 degree respectively find all the angles of the triangle

Answer 1

a+b=120-(1)
a-b=22 ; a=b+22
b+22+b=120.....by(1)
2b=120-22
2b=98
b=49

Answer 2

Let angles are x and y,

According to the question,

x + y = 120
x - y = 22
_________
2x = 142
_________

x = 142/2

x = 71°

Putting the value of x in x + y

x + y = 120

71 + y = 120

y = 120 - 71

y = 49°

×××××××××××××××××××××××××

We know, sum of all Angles of a triangle = 180°


71 + 49 + 3rd angle = 180

3rd angle = 180-120

3rd angle =60°

=================

Angles are :-

71°, 49°, 60°


I hope this will help you


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