The sum and difference of two sides of a triangle is 52 cm and 28 cm. If the third side of the
angle is 36 cm. Then the area of the triangle is
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1
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x+y=52
x-y=28
so, x=40 and y=12 by solving we get
s=a+b+c/2=88/2=44
Area of ∆=√44(44-12)(44-36)(44-40)=212.26cm²
Answered by
4
Answer:
1. 9:16
2. 4:9
Step-by-step explanation:
1 ratio of r = 3:4
ratio of there areas = πr²/πR²
= r²/R²
= 3²/4²= 9/16
2 . 2πr/2πR = r/R = 2/3
πr²/πR² = r/R = 2/3
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