The sum and difference of two sides of a triangle is 52 cm and 28 cm. If the third side of the
angle is 36 cm. Then the area of the triangle is
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x+y=52
x-y=28
so, x=40 and y=12 by solving we get
s=a+b+c/2=88/2=44
Area of ∆=√44(44-12)(44-36)(44-40)=212.26cm²
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When the values of the three sides of the triangle are given, then we can find the area of that triangle by using Heron's Formula. Refer to the section 'Area of a triangle by Heron's formula' mentioned in this article to get a complete idea.
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