The sum and product.... answer this
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Sum of the zeroes = - b/a = - 3
b = 3a --> ( i )
Product of the zeroes = c/a = 2
c = 2a --> ( ii )
Now, adding ( i ) and ( ii ),
b + c = 3a + 2a
b = 3a --> ( i )
Product of the zeroes = c/a = 2
c = 2a --> ( ii )
Now, adding ( i ) and ( ii ),
b + c = 3a + 2a
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