Question

The sum and,product of the roots of the quadratic equation 3x2-9x+5=0 is

Answer 1

Given quadratic equation,

${3x}^{2} - 9x + 5 \: = \: 0$

Let,

• a = 3
• b = -9
• c = 5

⟹ Sum of the zeros : α + ß = -b/a = -(-9)/3 = 9/3 = 3

⟹ Product of the zeros : αß = c/a = 5/3

Hence, it is solved....

$i \: hope \: it \: hepls \: you \: \: ....$

Step-by-step explanation:

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Answer 2

$\large \bold \green{ \underline{answer}} \\ \\ \implies \bold{sum \: \: of \: \: roots \: \: = \: \frac{ - b}{a} = 3 } \\ \\ \implies \bold{product \: \: of \: \: roots \: = \: \frac{c}{a} = \frac{5}{3} } \\ \\ \implies \bold \green{explanation} \\ \\ \implies \bold{3 {x}^{2} - 9x + 5 } \\ \\ \implies \bold{sum \: \: of \: \: roots \: \: of \: \: equation \: = \frac{ - b}{a} = 3 } \\ \\ \implies \bold{products \: \: of \: \: roots \: \: of \: \: equation \: = \frac{c}{a} = \frac{5}{3} } \\ \\ \implies \bold \green{verification} \\ \\ \implies \bold{formula \: \: of \: \: quadratic \: \: polynomial} \\ \\ \implies \bold{ {x}^{2} - ( \alpha + \beta )x + \alpha \beta } \\ \\ \implies \bold{ {x}^{2} - (3)x + \frac{5}{3} = 0 } \\ \\ \implies \bold{3 {x}^{2} - 9x + 5 = 0 } \\ \\ \implies \bold \green{ \boxed{verified}}$