Question

the sum and product of the zero of a quadratic polynomial are 2 and -15 respectively. The quadratic polynomial

Answer 1

Answer:

Using formula

$\boxed{{x}^{2} - (sum\:of\:roots)x + product\: of \: roots = 0}$

Then according to questions:-

x² - [ 2 + (-15)]x + 2 × (-15) = 0

x² -(-13)x + (-30) = 0

x² + 13x - 30 = 0

Therefore , the equation:-

$\huge\boxed{{x}^{2} + 13x - 30 = 0 }$