Question

the sum and product of the zeroes of polynomial 9x^2-5 respectively are
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Answer 1

Step-by-step explanation:

f(x)=9x^2 - 5

so,

sum of the zeroes

alpha + beta = -b/a i.e. -(coefficient of x)/coefficient of x^2

= 0/9 ,as there is no cefficient of x

product of the zeroes

alpha*beta = c/a i.e. constant term/coefficient of x^2

= -5/9

So,

Sum of the zeroes = 0/9

Product of the zeroes = -5/9