Question

The sum and product of the zeroes of the polynomial 9x^2 -5 respectively are
0,-9/5
0,9/5
0,59
0,-5/9

Answer 1

Answer:

d

Step-by-step explanation:

d is the ryt answer.....

Answer 2

Given :-

Polynomial P(x) = 9x² - 5

P(x) can be written like this also.

P(x) = 9x² - 0.x - 5

As we know that, Sum of zeroes.

$\alpha + \beta = \dfrac{-b}{a}$

$\alpha + \beta = \dfrac{0}{9}$

Again, Product of zeroes.

$\alpha\beta = \dfrac{c}{a}$

$\alpha\beta = \dfrac{-5}{9}$

Hence,

(4th) Option is Correct.

i.e. (0, -5/9)