Question

The sum and product of the zeroes of the quadratic polynomial 4x*-5x -1 are (respectively) *​

Answer 1

Step-by-step explanation:

In EQn a=4,b=-5,c=-1

So,sum 9f zeroes=-b/c=5/1=5

product 9f zeroes=a/c=4/1=4

Answer 2

Step-by-step explanation:

Given the quadratic polynomial,

$\sf \: 4 {x}^{2} - 5x - 1$

$\sf \: sum \: of \: zeroes \: \alpha + \beta = - \frac{coefficient \:of \: x}{coefficient \:of \: {x}^{2} } \\ \sf \implies \: \alpha + \beta = - \frac{ - 5}{4} \\ \sf \implies \: \pink{ \boxed{\alpha + \beta = \frac{5}{4} }}$

and

$\sf \: product \: of \: zeroes \: \alpha \beta = \frac {constant \: term}{coefficient \:of \: \: {x}^{2} } \\ \sf \implies \: \alpha \beta = \frac{ - 1}{x} \\ \sf \implies \: \green{ \boxed{ \alpha \beta = - \frac{1}{4} }}$