Question

the sum and product of the zeros of polynomial 9x^-5 repetitively are:​

Answer 1

Answer:

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answer will 0.

\huge{Explanation}Explanation

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9x²-5

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9x²-5= 0

9x²= 5

x²= \bf\frac{5}{9}

9

5

x= \bf\sqrt{\frac{5}{9}}

9

5

or x = \bf-\sqrt{\frac{5}{9}}−

9

5

so Addition of zeros

\bf\sqrt{\frac{5}{9}}

9

5

\bf-\sqrt{\frac{5}{9}}−

9

5

= 0

Answer 2

Answer:

first answer is correct