Question

The sum and product of the zeros of The polynomial 6x^2-x-2 are

Answer 1

Answer:

$sum \: of \: zeroes = \frac{1}{6} \\ product \: of \: zeroes = \frac{ - 1}{3}$

Step-by-step explanation:

$a = 6 \: and \: b = - 1 \: and \: c = - 2 \\ \\ = > \alpha + \beta = \frac{ - b}{a} \\ \\ = > \frac{ - ( - 1)}{6} \\ \\ = > \frac{1}{6} \\ \\ = > \alpha \beta = \frac{c}{a} \\ \\ = > \frac{ - 2}{6} \\ \\ = > \frac{ - 1}{3}$

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