Question

The sum and product of zeoes of quadratic polynomial x^+7x+10 is​

Answer 1

Answer:

heya mate ☺

$x ^{2} + 7x + 10 = 0 \\ = > x ^{2} + (5 + 2)x + 10 = 0 \\ = > x ^{2} + 5x + 2x + 10 = 0 \\ = > x(x + 5) + 2(x + 5) = 0 \\ = > (x + 5) (x + 2) = 0 \\ \\ either \: x \: = - 5 \\ or \: x = - 2$

So sum of two zeroes :

(-5)+(-2)

= -5 - 2

= - 7

And product of two zeroes :

(-5) * (-2)

= 10

Hope it helps u mate ✌

kEeP sHiNiNg kEeP SMiLiNg ☺

Answer 2

$\huge\bold\pink{AnswEr}$

Given :

We need to calculate the sum and product of zeroes of quadratic polynomial x^+7x+10

Solution :

Let the roots of the given quadratic equation be \alpha and \beta.

Therefore,

The sum of zeroes of the equation,

$s = \alpha + \beta = - \frac{7}{1} = - 7$

And the product of zeroes of the equation,

$p = \alpha \beta = \frac{10}{1} = 10$

Explanation :

If the quadratic equation is,

$ax^{2} + bx + c = 0$

Then the sum of the roots would be

$- \frac{b}{a}$

And the product of the roots would be

$\frac{c}{a}$

Applying this the answer can be found.

Thanks :)