Question

the sum and product of zeroes of p(x) = 63x^2 - 7x - 9 are S and P respectively.find S and P

plz answer correctly I will mark it brainlist answer .
nd if the answer was wrong then I will report. ​

Answer 1

AnswEr :

$\:\bullet\:\sf\ Given \: polynomial = 63x^2 - 7x - 9$

$\:\bullet\:\sf\ Sum \: of \: zeroes(S) =?$

$\:\bullet\:\sf\ Product \: of \: zeroes(P) =?$

$\rule{100}1$

$\underline{\bigstar\:\textsf{According \: to \: given \: in \: question:}}$

$\normalsize\star{\boxed{\sf{Sum \: of \: zeroes = \frac{-(Coefficient \: of \: x)}{Coefficient \: of \: x^2} }}}$

$\normalsize\dashrightarrow\sf\ \alpha + \beta = \frac{-b}{a}$

$\normalsize\dashrightarrow\sf\ \alpha + \beta = \frac{-(-7)}{63}$

$\normalsize\dashrightarrow\sf\ \alpha + \beta = \frac{\cancel{7}}{\cancel{63}}$

$\normalsize\dashrightarrow\sf\ \alpha + \beta = \frac{1}{9}$

$\normalsize\dashrightarrow\sf\ Sum \: of \: zeroes = \frac{1}{9}$

$\normalsize\dashrightarrow{\underline{\boxed{\frak \red{Sum \: of \: zeroes(S) = \frac{1}{9}}}}}$

$\normalsize\star{\boxed{\sf{Product \: of \: zeroes = \frac{Constant\: term}{Coefficient \: of \: x^2} }}}$

$\normalsize\dashrightarrow\sf\ \alpha\beta = \frac{c}{a}$

$\normalsize\dashrightarrow\sf\ \alpha\beta = \frac{-9}{63}$

$\normalsize\dashrightarrow\sf\ \alpha\beta = \frac{-1}{7}$

$\normalsize\dashrightarrow\sf\ Product \: of \: zeroes = \frac{-1}{7}$

$\normalsize\dashrightarrow{\underline{\boxed{\frak \red{Product \: of \: zeroes(P) = \frac{-1}{7}}}}}$

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

Answer 2

Answer:

sum = -(coefficient of x) / coefficient of x^2

product = constant term/ coefficient of x^2

sum of zeroes is -(-7)/63 = 7/63= 1/9 = S

product of zeroes is -9/63= -1/7 = P.

I HOPE THIS WILL HELP YOU. ..