Question

the sum and product of zeros of polynomials 9x square–5

Answer 1

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answer will 0.

$\huge{Explanation}$

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9x²-5

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9x²-5= 0

9x²= 5

x²= $\bf\frac{5}{9}$

x= $\bf\sqrt{\frac{5}{9}}$

or x = $\bf-\sqrt{\frac{5}{9}}$

so Addition of zeros

$\bf\sqrt{\frac{5}{9}}$ $\bf-\sqrt{\frac{5}{9}}$ = 0