Question

the sum and product of zeros of quadratic polynomial P of x is equal to X square + bx + c are -3 and 2 respectively show that b + c = 5a​

Answer 1

Answer:

p(x) = ax^2 + bx + c

Let 1st zero be @

& 2nd zero be ©

Now,

Sum of zeroes = @+© = -3+2 = -1

We know, Sum of zeroes = -b/a

$o ,

-b/a = -1

-b = -a

b = a ....(1)

Similarly,

Product of zeroes = @© = (-3)(2) = -6

Hence,

c/a = -6

c = -6a

=> b+a = a-6a = -5a

Hence, Proved.