Question

the sum and product respectively of zeroes of the polynomial
${x } ^{2} - 4x + 3$
​

Answer 1

Sum and Product of the zeroes are -4 and 3.

Step-by-step explanation:

${x}^{2} - 4x + 3$

$Let \: the \: two \: zeroes \: be \: \alpha \: and \: \beta .$

$a = 1, b = -4, c = 3.$

$Sum \: of \: the \: zeroes = ( \alpha + \beta ) = \frac{ - b}{a}$

$= - ( \frac{ - 4}{1})$

$= - 4.$

$Product \: of \: the \: zeroes = ( \alpha . \beta ) = \frac{c}{a}$

$= \frac{3}{1}$

$= 3.$