Question

the sum and the product of quadratic polynomial are underoot 2 and -3/2 respectively. find the quadratic polynomial​

Answer 1

Step-by-step explanation:

sum of the zeores =√

product of the zeores=-3/2

now

$x {}^{2} + (sum \: of \: the \: zeroes)x + (product \: of \: the \: zeroes) = 0$

$x {}^{2} + \sqrt{2} x + (\frac{ - 3}{2} ) = 0$

$\frac{2 {x}^{2} + 2 \sqrt{2}x - 3 }{2} = 0$

$2x {}^{2} + 2 \sqrt{2} x - 3 = 0$