The sum and the product of the zeroes of the polynomia f(x)= 4x^2− 27x + 3k^2 are equal. Find the value (s)k
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anuhkamoon86:
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Given Polynomial f(x)= 4x^2− 27x + 3k^2
we know that sum of Zeroes of an Equation
= -b/a
= -(-27)/4
=27/4
product of Zeroes = c/a = 3k^2 /4
Given that..
The sum and the product of the zeroes of the polynomia f(x)= 4x^2− 27x + 3k^2 are equal.
so by equating values..
27/4 = 3k^2 /4
cancel 4 on both sides..
27 = 3k^2
27/3 = k^2
9= k^2
√9 = k
+3 or -3 = k
we know that sum of Zeroes of an Equation
= -b/a
= -(-27)/4
=27/4
product of Zeroes = c/a = 3k^2 /4
Given that..
The sum and the product of the zeroes of the polynomia f(x)= 4x^2− 27x + 3k^2 are equal.
so by equating values..
27/4 = 3k^2 /4
cancel 4 on both sides..
27 = 3k^2
27/3 = k^2
9= k^2
√9 = k
+3 or -3 = k
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