The sum and the product of zeroes of a quadratic polynomial are -8 and 12 respectively. Find the zeroes of polynomial
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alpha+beta= -8 = -b/a
alpha beta = 12 = c/a
by the formula
ax^+bx+c =0
a=1;b=8;c=12
so the quadratic equation is 1x^+8+12=0
soving quadratic equations
1x^+8x+12=0(by middle term splitting method)
firstly multiply last term and first term that is 12×1x^=12x^
now when we factorise 12x^ by 6x ×2x we get 12x^ and when we add the multiples 6 and 2 we should get 8.So now the equation is 1x^+6x+2x+12=0
now take out common term
x( x+6)+ 2( x+6)=0
(x+2) (x+6)
x+2=0. x+6=0
x= -2 x= -6
So the zeores of polynomial is
-2. and -6
hope may help you ☺️
thank you
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