Question

the sum area of the square of side 3a and 3 b will be

Answer 1

Answer:

9(a²+b²)

Step-by-step explanation:

area of sq 1=(3a)²=9a²

area of sq 2=(3b)²=9b²

sum=9a²+9b²=9(a²+b²)

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Answer 2

Answer:

sum of area of the squares of sides '3a' and '3b' will be 9 ( a² + b² )  

Step-by-step explanation:

given that :

there are two squares ,

side length of a first square is 3a

side length of a second square is 3b

area of first square is (side)² = (3a)² = 9a²

area of second square = (3b)² = 9b²

sum of area of two given squares is (9a² + 9b² )

sum of area of the squares of sides 3a and 3b will be  9 ( a² + b² )