Question

the sum at 5term at ap is55 the fourth term at the sequence is five more than the sum of the next two terms then find the ap​

Answer 1

Answer:

sn=n/2(a+l)

Step-by-step explanation:

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Answer 2

Answer:

A.P. is 175 , 145 , 155 , 85 , 55 ........

Step-by-step explanation:

let,

The required A.P. be a , (a+d) (a+2d) .........

tn = a + (n-1) d

t5= a + 4d

a + 4d = 55 _______( 1 )

Now,

By given condition :

t4 = t5 + t6 + 5

a + 3d = a + 4d + a + 5d + 5

a - a + 3d - 5d = 55 + 5 ___ { from ( 1 ) } -2d = 60

d = -30 ________( 2 )

From ( 1 ) and ( 2 ) :

a + 4(-30) = 55

a - 120 = 55

a = 55 + 120

a = 175

Here,

a = 175

d = -30

Therefore, the required A.P. is

175 , 145 , 115 , 85 , 55 , 25 ............