The sum BC ,CA and AB of triangle ABC, are produced in order, forming exterior angle ACD,angle BAE, and angle CBF show that angle ACD + angle BAE + angle CBF =360°
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Step-by-step explanation:
(BC+CA+AB)+(CD+DA+AC)+(AE+EA+BA)+(BF+FC+CB)=90°+90°+90°+90°
=360°
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