Question

The sum digits of the two-digit number is 17. The new number obtained by reversing the digits is 9 more than the original number find the number.​

Answer 1

Digit at ten - x

unit-y

original number 10x+y

interchange 10y+x

x+y=17....1.

10x+y+9=10y+x

9x-9y=-9

x-y= -1 ....2

divided both sides with 9

adding 1 and 2

x+y=17

x-y=-1

2x=16

x=8

put x=8 in 1

8+y=17

y=9

Answer 2

Step-by-step explanation:

two digit number=10x+y

reversing=10y+X

case1

X+y=17

case2

10y+x=10x+y+9

10y-y=10x-x+9

9y=9x+9

9y-9x=9

9(y-x)=9

y-x=1

y=1+X

using this in case 1

we get,

x+1+X=17

2x=17-1

x=8

therefore y=9

so, number=10x+y

=89