the sum exterior angles of a polygon is 360⁰ (how ?)
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The sum of the interior angles of a regular polygon with n sides is 180(n-2). So, each interior angle has measure 180(n-2) / n. Each exterior angle is the supplement to an interior angle. Sum of exterior angles = n(360 / n) = 360.
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Summed, the exterior angles equal 360 degreEs. A special rule exists for regular polygons: because they are equiangular, the exterior angles are also congruent, so the measure of any given exterior angle is 360/n degrees.
( or )
The sum of exterior angles in a polygon is always equal to 360 degrees. Therefore, for all equiangular polygons, the measure of one exterior angle is equal to 360 divided by the number of sides in the polygon
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