Question

The sum first 61 terms of an Arithmetic progression is 4880. Find 31st term .​

Answer 1

Answer:

80

Step-by-step explanation:

sum of first 61 terms = 61/2(2a + (61-1)d)

4880 = 61/2(2a + 60d)

4880 = 61(a + 30d)

80 = a + 30d

now,

31rst term = a + (n-1)d

a + (31-1)d

a + 30d

80

I m not sure about the answer so u can recheck it