Question

the sum for which the simple interest for 3 years at 9% per annum is Rs 4320​

Answer 1

ANSWER-

Given,

• time period= 3years
• Rate =9%
• Simple Interest= Rs. 4320

Find -

• The Principle amount= ?

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$\huge{\bf{\underline{\red{SOLUTION}}}}$

Let principle = P

Rate of interest = R

Time period =T

Interest = I

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We know,

$I= \frac{PTR}{100}$

thus putting the values we get,

$4320 = \frac{P \times 3 \times 9}{100} \\ \implies \: 4320 \times 100 = 3 \times 9 \times P \\ \implies \: P = \frac{4320 \times 100}{3 \times 9} \\ \implies \: P= \frac{1440 \times 100}{9} \\ \implies \: P= 160 \times 100 \\ \implies \: P= 16000 \: rs$

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The amount is $\huge{\red{\boxed{\boxed{16000Rs.}}}}$

Answer 2

$\huge\underline\mathbb{SOLUTION:-}$

Answer:

• Principle Amount = Rs.16,000

Given:

• T = 3 Years
• R = 9 %
• SI = Rs. 4320

Here,

• T is used for Time.
• R is used for Rate.
• SI is used for Simple Interest.

Need To Find:

• Principle Amount = ?

Explanation:

Let,

• Principle as P.
• Rate of Interest as R.
• Time of period as T.
• And, Simple Interest as SI.

$\underline \mathsf \red {We\:Know\:the\:Formula\: :-}$

$\implies \mathsf {SI = \frac{P \times T \times R}{100}}$

Putting the values according to formula then we get,

$\implies \mathsf {4320 =\frac{P \times 3 \times 9}{100} }$

$\implies \mathsf { 4320 \times 100 = 3 \times 9 \times P}$

$\implies \mathsf {P =\frac{4320 \times 100}{3 \times 100} }$

$\implies \mathsf {P =\frac{1440 \times 100}{9} }$

$\implies \mathsf {P = 160 \times 100}$

$\implies \mathsf {P = 16,000}$

Therefore,

• Principle Amount = Rs. 16,000