Question

The sum four consecutive numbers in April is 32 and the ratio of the product of the first and last term to the product of two middle term is 7:15 find the number

Answer 1

It comes in board exams.
Numbers are as follows -
2,6,10,14

Answer 2

Yeah ur answer is


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Let the four consecutive numbers in AP be (a-3d),(a-d),(a+d) and (a+3d)

So, According to question

a+3d+a-d+a+d+a+3d=32
4a=32
a=32/4
a=8----------(1)

Now,
(a-3d)(a+3d)/(a-d)(a+d)=7/15

15(a2-9d2)=7(a2-d2)
15a2-135d2=7a2-7d2
8a2=128d2

Putting the value of a from equation 1

8(8)2=128d2
128d2=512
d2=512/128
d2=4
d=√4
d=2

So no. are,

8-6=2
8+2=6
8+2=10
8+6=14
{Note:- Here (a2-9d2) in this the 2 denoted square}

Hope it helps Mark as brainliest