Question

the sum if three consecutive odd numbers is 567 . find the number​

Answer 1

Let first odd number is x. Then

X+(X+2)+(X+4)+(X+6)+(X+8)+ (X+10)+(X+12)=567

7x+42=567

7x=567–42=525

x=525/7=75

The seven consecutive odd numbers are

75,77,79,81,83,85 and 87

Answer 2

Answer:

Let the number be x, x + 2 and x + 4

x + x + 2 + x + 4 = 567

3x + 6 = 567

3x = 567 - 6

x = 561/3 = 187

Numbers are, 187, 189, 191