Question

The sum of 1+1/3+1/3^2+1/3^3 +.....+1/3^n^-1

Please Answer this question​

Answer 1

Step-by-step explanation:

r = 1/3

a = 1

Sn = a[ 1-(r^n) ]/(1-r)

= [ 1- (1/3)^n-1 ] / (1-1/3)

= 1.5 [3^(n-1) -1]/3^(n-1)