The sum of 10 consecutive cubes starting from 1
Answers
Answered by
55
hey mate here is your answer -
1+8+27+64+125+216+343+512+729+1000
=3025
I hope it helps you !!
1+8+27+64+125+216+343+512+729+1000
=3025
I hope it helps you !!
rkbhati2011p8anya:
Thank u sooo much..helped a lot
Answered by
18
answer will be (n(n+1)/2 )^2
(10(10+1)/2)^2= (10×11/2)^2
(5×11)^2= 55^2
= 3025
hope it helps
(10(10+1)/2)^2= (10×11/2)^2
(5×11)^2= 55^2
= 3025
hope it helps
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