Question

The sum of 10 consecutive integers ia 10 more than the twice the smallest integers find all integers.
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Answer 1

Step-by-step explanation:

Let the three consecutive integers be n , n+1,n+2

so n+n+1+n+2=3n+3

From the data , 3n+3=2n. ( since n is the smallest integer)

So, 3n +3=2n

3n-2n+3=0

n+3=0

n=(-3)

The other two integers :-

n+1=(-3+1)=(-2)

n+2=(-3+2)=(-1)

ANSWER :- The three integers are (-3),(-2),(-1)

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