The sum of 10 terms of 5+8+11+....
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Answered by
14
ANSWER =
Sn = ?
n= 10
a = 5
d = 8 - 5
= 3
FORMULA : Sn = n/2 ( 2a + (n-1) d)
Sn = 10/2 [ 2 x 5 ( 10 - 1 ) 3 ]
Sn = 5 ( 10 x 9 x 3 )
Sn = 5 x 10 x 9 x 3
Sn = 1350
sum = 1350
HOPE IT HELPS
☜☆☞
Sn = ?
n= 10
a = 5
d = 8 - 5
= 3
FORMULA : Sn = n/2 ( 2a + (n-1) d)
Sn = 10/2 [ 2 x 5 ( 10 - 1 ) 3 ]
Sn = 5 ( 10 x 9 x 3 )
Sn = 5 x 10 x 9 x 3
Sn = 1350
sum = 1350
HOPE IT HELPS
☜☆☞
Soñador:
thanks
Answered by
13
HEY!
_______

Here,
a = 5
d = 8 - 5 => 3
n = 10
![s_{n} = \frac{10}{2}[2 × 5 + (10 - 1)3] s_{n} = \frac{10}{2}[2 × 5 + (10 - 1)3]](https://tex.z-dn.net/?f=+s_%7Bn%7D+%3D+%5Cfrac%7B10%7D%7B2%7D%5B2+%C3%97+5+%2B+%2810+-+1%293%5D)
![s_{n} = 5 [ 10 + 9 × 3] s_{n} = 5 [ 10 + 9 × 3]](https://tex.z-dn.net/?f=+s_%7Bn%7D+%3D+5+%5B+10+%2B+9+%C3%97+3%5D)
![s_{n} = 5 [ 10 + 27 ] s_{n} = 5 [ 10 + 27 ]](https://tex.z-dn.net/?f=+s_%7Bn%7D+%3D+5+%5B+10+%2B+27+%5D)


_______
Here,
a = 5
d = 8 - 5 => 3
n = 10
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