Question

the sum of 10terms of the GP 1, 2/3,4/9​

Answer 1

Answer:

$\huge{\boxed{\sf{S10=-1.05}}}$

Step-by-step explanation:

$\huge{\boxed{\sf{ SOLUTION- }}}$

$\huge{\boxed{\sf{G.P}}}$

$a = 1 \\ common \: ratio = \frac{a2}{a1} \\ c.r = \frac{ \frac{2}{3} }{1} \\ c.r = \frac{2}{3} \\ no.of \: terms \\ putting \: these \: values \: in \: sum \: of \: g.p \: terms \\ sn = \frac{a( {r}^{n} - 1) }{r - 1} \\ s10 = \frac{1( { (\frac{2}{3} })^{10} - 1)}{ \frac{2}{3} - \frac{1}{1} } \\ s10 = \frac{ {( \frac{2}{3} })^{10} - 1 }{ \frac{2 - 3}{3} } \\ s10 = \frac{ - 3}{1} \times \frac{1024}{59049} - \frac{1}{1} \\ s10 = \frac{ - 1024}{19683} - \frac{1}{1} \\ s10 = \frac{ - 1024 - 19683}{19683} \\ s10 = - 1.05$

$\huge{\boxed{\sf{S10=-1.05}}}$