Question

the sum of 11 consecutive numbers is 66 which is the largest of this number​

Answer 1

Answer:

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Answer 2

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One way is to set up an equation. Let n = one of the numbers and n+2 for the other number. This gives us the equation:

n + (n+2) = 66

2n+2 = 66

2n=64

n=32

n+2=34

The two consecutive two even integers that sum to 66 are 32 and 34.