Question

The sum of 11 results is 50 find the sum of the first 6 result is 30 and that of the last 6 is 48 find the 6th result.​

Answer 1

Answer:

Let the 6th result be x

Sum of first 6 = 30

Sum of last 6 = 48

No. of result = 11

So, the 6th result is common in both cases

Hence, if we subtract the sixth result from the sum of 30 and 48 the result will equal to 50.

Then, 50 = 30 + 48 - x

=> 50 = 78 - x

=> x = 78 - 50

=> x = 28

Sixth result = 28

Answer 2

Given: The sum of 11 results is 50 find the sum of the first 6 result is 30 and that of the last 6 is 48.

To find: The 6th result.​

Solution:

Let the sixth result be x. Now, the sum of all the results can be written as shown in the following equation.

$first 5 +x +last 5 = 50$

Similarly, the sum of the first 6 results can be written as follows.

$first 5 + x = 30$

Also, the sum of the last 6 results can be written as follows.

$x +last 5 = 48$

Using the first two equations, the sum of the last 5 results can be calculated as follows.

$first 5 +x +last 5 = 50$

$30 +last 5 = 50$

$last 5 = 20$

Now, using the third equation and the value of the sum of the last 5 results, x can be calculated.

$x +last 5 = 48$

$x + 20 = 48$

$x = 28$

Therefore, the 6th result is 28.