Question

the sum of 14 and 8 term of AP is 24 and sum of 6th and 10th term of AP is 44 find the first three term of an ap

Answer 1

a14 +a8 = 24
a+13d+a+7d=24
2a+20d =24.

a6+a10= 44
a+5d + a+9d= 44
2a+14d =44

2a+20d-2a-14d=24-44
6d=-20
d =-20/6
then
2a +14(-20/6)=44