Math, asked by Hema1111, 1 year ago

the sum of 15 terms of an ap is 240. then the 8th term is ---

Answers

Answered by Mausam11
11
the sum of 15 term=240
so, thesum of 1 term =240/15

sum of 8th term =240/15×8
=16×8=128
Answered by bhagyashreechowdhury
2

The 8th term is 16.

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Let's understand a few concepts:

To solve the given problem we will use the following formulas:

  • The sum of n terms of an A.P. is: \boxed{\bold{S_n = \frac{n}{2}[2a+(n-1)d] }}

  • The nth term of an A.P. is: \boxed{\bold{a_n = a + (n-1)d}}

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Let's solve the given problem:

The sum of 15 terms of an A.P. = 240

So, we get

S_ 1_5 =\frac{15}{2}[2a+(15-1)d]= 240

\implies\frac{15}{2}[2a+(15-1)d]= 240

\implies\frac{15}{2}[2a+14d]= 240

\implies 15[a+7d]= 240

\implies a+7d= \frac{240}{15}

\implies a+7d= 16\:.\:.\:.\:.\:(1)

Now,

The 8th term of the given A.P. will be,

= a_8

= a+ (8-1)d

= a+7d

  • from equation  (1), we get

= \bold{16}

Thus, the 8th term of the A.P. is 16.

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