Question

the sum of 15th term of an arithhmatic sequence is 40(A)find sum of 14th term and 16th term

Answer 1

Step-by-step explanation:

incomplete question more information needed

Answer 2

Answer:

Step-by-step explanation:

Let a= first term and d= common difference

Then

$\ 15^{th} \ term\\\\A_{15}=a+14d=40\\\\a+14d= 40-----------------------(1)\\\\Also \\\\A_{14}= a+13d\\\\and \ A_{16}=a+15d\\\\Thus \ A14+A16 = 2a+13d+15d=2a+28d\\\\=2(a+14d)\\\\\bf =2 \times 40=80$